How many aldol products (excluding stereoisom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is a mixed aldol condensation between propanal $(CH_3CH_2CHO)$ and benzaldehyde $(C_6H_5CHO)$.Propanal has $\alpha$-hydrogens,while b

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The reaction is a mixed aldol condensation between propanal $(CH_3CH_2CHO)$ and benzaldehyde $(C_6H_5CHO)$.Propanal has $\alpha$-hydrogens,while benzaldehyde does not.Possible products are:$1$. Self-aldol of propanal: $CH_3CH_2CH(OH)CH(CH_3)CHO$.$2$. Cross-aldol (propanal as nucleophile,benzaldehyde as electrophile): $C_6H_5CH(OH)CH(CH_3)CHO$.Since benzaldehyde cannot form an enolate,it cannot act as a nucleophile,so no other cross-aldol or self-aldol products are formed.Thus,there are $2$ aldol products obtained.

How many aldol products (excluding stereoisomers) are obtained in the given reaction?
$CH_3-CH_2-CHO + C_6H_5CHO \xrightarrow[0-5 \ ^{\circ}C]{OH^{\ominus}} ?$

Similar Questions

Which of the following reactions gives a carboxylate ion in their reaction mixture?

The structure of $(B)$ is

Aldol condensation involving $CH_3-CHO + CH_3-CHO$ gives the product:

The above compounds can be differentiated by the following reagent:

Which of the following reactions cannot be used to convert $R_2CO$ to $R_2CH_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

How many aldol products (excluding stereoisomers) are obtained in the given reaction?$CH_3-CH_2-CHO + C_6H_5CHO \xrightarrow[0-5 \ ^{\circ}C]{OH^{\ominus}} ?$